interceptos ((z-8)^2)/(z^2-64)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for expand factor rationalize

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range 1−sec²(x)

Solution

f(x)≤ 0

Interval Notation

(−∞ , 0]

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Function range definition

The set of values of the dependent variable for which a function is defined

Find the minimum and maximum value in each defined interval and unite the results

Domain of 1−sec²(x) : πn≤ x<π2 +πn or π2 +πn<x<π+πn

Extreme Points of 1−sec²(x): Maximum(πn, 0)

Find the range for the interval 0≤ x<π2 : −∞ <f(x)≤ 0

Find the range for the interval π2 <x<π: −∞ <f(x)≤ 0

Combine the ranges of all domain intervals to obtain the function range

f(x)≤ 0 or f(x)≤ 0

f(x)≤ 0

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domain 1−sec²(x)

periodicity 1−sec²(x)

amplitude 1−sec²(x)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

interceptos ((z-8)^2)/(z^2-64)

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interceptos ((z-8)^2)/(z^2-64)

Solution

Solution steps

Solve instead

Number Line

Graph