What is the extreme f(x)=((x))/((6x+2)),5<= x<= 8 ?

The extreme f(x)=((x))/((6x+2)),5<= x<= 8 is Minimum(5, 5/32),Maximum(8, 4/25)

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extreme f(x)=((x))/((6x+2)),5<= x<= 8

extreme

Minimum (5, \frac{5}{32}), Maximum (8, \frac{4}{25})

Solution steps

Find the critical points:

x = 5, x = 8

Domain of

\frac{x}{6 x + 2}, 5 \leq x \leq 8 : 5 \leq x \leq 8

Find intervals:

Increasing

: 5 < x < 8

Plug the extreme point

x = 5

into

\frac{x}{6 x + 2} \Rightarrow y = \frac{5}{32}

Minimum (5, \frac{5}{32})

Plug the extreme point

x = 8

into

\frac{x}{6 x + 2} \Rightarrow y = \frac{4}{25}

Maximum (8, \frac{4}{25})

Minimum (5, \frac{5}{32}), Maximum (8, \frac{4}{25})

What is the extreme f(x)=((x))/((6x+2)),5<= x<= 8 ?
The extreme f(x)=((x))/((6x+2)),5<= x<= 8 is Minimum(5, 5/32),Maximum(8, 4/25)