What is the extreme f(x)=1.4te^{-2.9t} ?

The extreme f(x)=1.4te^{-2.9t} is Maximum(10/29 ,0.1775969716)

extreme f(x)=1.4te^{-2.9t}

extreme points

f (x) = 1.4 t e^{- 2.9 t}

Maximum (\frac{10}{29}, 0.1775969716)

Solution steps

Find the critical points:

t = \frac{10}{29}

Domain of

1.4 t e^{- 2.9 t} : - \infty < t < \infty

Find intervals:

Increasing

: - \infty < t < \frac{10}{29},

Decreasing

: \frac{10}{29} < t < \infty

Plug the extreme point

x = \frac{10}{29}

into

1.4 t e^{- 2.9 t} \Rightarrow y = 0.1775969716

Maximum (\frac{10}{29}, 0.1775969716)

f (x) = 2 x^{3} - 9 x^{2} - 24 x + 9, - 2 \leq x \leq 5

f (x) = \frac{9 x}{x - 4}

f (x) = x e^{\frac{- x ^{2}}{32}}

2400 = 30 x \cdot 10 y

f (- 1.2) = 3 p^{3} + 4 q^{3} - 2 p^{2} q - 4 p - 5 q

What is the extreme f(x)=1.4te^{-2.9t} ?
The extreme f(x)=1.4te^{-2.9t} is Maximum(10/29 ,0.1775969716)