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العربية

(sin^2(x))/(1-cos^2(x))=cot(x)

Solução

\frac{sin ^{2} ( x )}{1 - cos ^{2} ( x )} = cot (x)

x = \frac{π}{4} + πn

Graus

x = 4 5^{\circ} + 18 0^{\circ} n

Passos da solução

\frac{sin ^{2} ( x )}{1 - cos ^{2} ( x )} = cot (x)

Subtrair

cot (x)

de ambos os lados

\frac{sin ^{2} ( x )}{1 - cos ^{2} ( x )} - cot (x) = 0

Simplificar

\frac{sin ^{2} ( x )}{1 - cos ^{2} ( x )} - cot (x) : \frac{sin ^{2} ( x ) - cot ( x ) ( 1 - cos ^{2} ( x ) )}{1 - cos ^{2} ( x )}

\frac{sin ^{2} ( x )}{1 - cos ^{2} ( x )} - cot (x)

Converter para fração:

cot (x) = \frac{cot ( x ) ( 1 - cos ^{2} ( x ) )}{1 - cos ^{2} ( x )}

= \frac{sin ^{2} ( x )}{1 - cos ^{2} ( x )} - \frac{cot ( x ) ( 1 - cos ^{2} ( x ) )}{1 - cos ^{2} ( x )}

Já que os denominadores são iguais, combinar as frações:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{sin ^{2} ( x ) - cot ( x ) ( 1 - cos ^{2} ( x ) )}{1 - cos ^{2} ( x )}

\frac{sin ^{2} ( x ) - cot ( x ) ( 1 - cos ^{2} ( x ) )}{1 - cos ^{2} ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

sin^{2} (x) - cot (x) (1 - cos^{2} (x)) = 0

Reeecreva usando identidades trigonométricas

sin^{2} (x) - (1 - cos^{2} (x)) cot (x)

Utilizar a identidade trigonométrica pitagórica:

1 = cos^{2} (x) + sin^{2} (x)

1 - cos^{2} (x) = sin^{2} (x)

= sin^{2} (x) - cot (x) sin^{2} (x)

sin^{2} (x) - cot (x) sin^{2} (x) = 0

Fatorar

sin^{2} (x) - cot (x) sin^{2} (x) : - sin^{2} (x) (cot (x) - 1)

sin^{2} (x) - cot (x) sin^{2} (x)

Fatorar o termo comum

- sin^{2} (x)

= - sin^{2} (x) (- 1 + cot (x))

- sin^{2} (x) (cot (x) - 1) = 0

Resolver cada parte separadamente

sin^{2} (x) = 0 or cot (x) - 1 = 0

sin^{2} (x) = 0 : x = 2 πn, x = π + 2 πn

sin^{2} (x) = 0

Aplicar a regra

x^{n} = 0 \Rightarrow x = 0

sin (x) = 0

Soluções gerais para

sin (x) = 0

sin (x)

tabela de periodicidade com ciclo de

2 πn

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Resolver

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

cot (x) - 1 = 0 : x = \frac{π}{4} + πn

cot (x) - 1 = 0

Mova

1

para o lado direito

cot (x) - 1 = 0

Adicionar

1

a ambos os lados

cot (x) - 1 + 1 = 0 + 1

Simplificar

cot (x) = 1

cot (x) = 1

Soluções gerais para

cot (x) = 1

cot (x)

tabela de periodicidade com ciclo de

πn

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

Combinar toda as soluções

x = 2 πn, x = π + 2 πn, x = \frac{π}{4} + πn

Dado que a equação é indefinida para:

2 πn, π + 2 πn

x = \frac{π}{4} + πn

cos^{2} (x) + cos^{3} (x) + cos^{4} (x) + cos^{5} (x) = 0

sin^{2} (x) - 4 sin (x) = - 3

1 + 7 sinh (x) = 4 cosh^{2} (x)

sin^{2} (x) - 1 + 2 cos (2 x) - cos^{2} (x) = 0

cos^{2} (x) + 6 cos (x) + 5 = 0