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Guias de estudo > College Algebra CoRequisite Course

Add, Subtract, and Multiply Complex Numbers

Learning Outcomes

  • Add and subtract complex numbers
  • Multiply complex numbers
Just as with real numbers, we can perform arithmetic operations on complex numbers. To add or subtract complex numbers, we combine the real parts and combine the imaginary parts.

recall doing operations on algebraic expressions

Performing arithmetic on complex numbers is very similar to adding, subtracting, and multiplying algebraic variable expressions. Recall that doing so involves combining like terms, carefully subtracting, and using the distributive property. Complex numbers of the form a+bia+bi each contain a real part aa and an imaginary part bibi. Real parts are like terms with real parts. Likewise, imaginary parts are like with other imaginary parts.

A General Note: Addition and Subtraction of Complex Numbers

Adding complex numbers:

(a+bi)+(c+di)=(a+c)+(b+d)i\left(a+bi\right)+\left(c+di\right)=\left(a+c\right)+\left(b+d\right)i

Subtracting complex numbers:

(a+bi)−(c+di)=(a−c)+(b−d)i\left(a+bi\right)-\left(c+di\right)=\left(a-c\right)+\left(b-d\right)i

How To: Given two complex numbers, find the sum or difference.

  1. Identify the real and imaginary parts of each number.
  2. Add or subtract the real parts.
  3. Add or subtract the imaginary parts.

Example: Adding Complex Numbers

Add 3−4i3 - 4i and 2+5i2+5i.

Answer: We add the real parts and add the imaginary parts.

(3−4i)+(2+5i)=(3+2)+(−4+5)i=5+i\left(3 - 4i\right)+\left(2+5i\right)=\left(3+2\right)+\left(-4+5\right)i=5+i

Try It

Subtract 2+5i2+5i from 3−4i3 - 4i.

Answer: (3−4i)−(2+5i)=1−9i\left(3 - 4i\right)-\left(2+5i\right)=1 - 9i

[ohm_question]61710[/ohm_question]
https://youtu.be/SGhTjioGqqA

Multiplying Complex Numbers

Multiplying complex numbers is much like multiplying binomials. The major difference is that we work with the real and imaginary parts separately.

Multiplying a Complex Number by a Real Number

Let’s begin by multiplying a complex number by a real number. We distribute the real number just as we would with a binomial. So, for example,

\begin{align}3(6+2i)&=(3\cdot6)+(3\cdot2i)&&\text{Distribute.}\\&=18+6i&&\text{Simplify.}\end{align}

How To: Given a complex number and a real number, multiply to find the product.

  1. Use the distributive property.
  2. Simplify.

Example: Multiplying a Complex Number by a Real Number

Find the product 4(2+5i)4\left(2+5i\right).

Answer:

4(2+5i)=(4⋅2)+(4⋅5i)=8+20i4\left(2+5i\right)=\left(4\cdot 2\right)+\left(4\cdot 5i\right)=8+20i

Try It

Find the product −4(2+6i)-4\left(2+6i\right).

Answer: −8−24i-8 - 24i

[ohm_question]40462[/ohm_question]

Multiplying Complex Numbers Together

Now, let’s multiply two complex numbers. We can use either the distributive property or the FOIL method. Recall that FOIL is an acronym for multiplying First, Outer, Inner, and Last terms together. Using either the distributive property or the FOIL method, we get

(a+bi)(c+di)=ac+adi+bci+bdi2\left(a+bi\right)\left(c+di\right)=ac+adi+bci+bd{i}^{2}

Because i2=−1{i}^{2}=-1, we have

(a+bi)(c+di)=ac+adi+bci−bd\left(a+bi\right)\left(c+di\right)=ac+adi+bci-bd

To simplify, we combine the real parts, and we combine the imaginary parts.

(a+bi)(c+di)=(ac−bd)+(ad+bc)i\left(a+bi\right)\left(c+di\right)=\left(ac-bd\right)+\left(ad+bc\right)i

How To: Given two complex numbers, multiply to find the product.

  1. Use the distributive property or the FOIL method.
  2. Simplify.

Example: Multiplying a Complex Number by a Complex Number

Multiply (4+3i)(2−5i)\left(4+3i\right)\left(2 - 5i\right).

Answer:

\begin{align}\left(4+3i\right)\left(2 - 5i\right)&=4\cdot 2 + 4\cdot \left(-5i\right)+3i\cdot2+3i\cdot \left(-5i\right)\\ &=8-20i+6i-15i^2\\&=8+15-20i+6i\\ &=23 - 14i\end{align}

Try It

Multiply (3−4i)(2+3i)\left(3 - 4i\right)\left(2+3i\right).

Answer: 18+i18+i

[ohm_question]3903[/ohm_question]
https://youtu.be/O9xQaIi0NX0

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