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Guias de estudo > ALGEBRA / TRIG I

Identifying the Intercepts on the Graph of a Line

Learning Outcomes

  • Identify the xx and yy-intercepts from the graph of a line
  • Identify the xx and yy-intercepts from the equation of a line
Every linear equation has a unique line that represents all the solutions of the equation. When graphing a line by plotting points, each person who graphs the line can choose any three points, so two people graphing the line might use different sets of points. At first glance, their two lines might appear different since they would have different points labeled. But if all the work was done correctly, the lines will be exactly the same line. One way to recognize that they are indeed the same line is to focus on where the line crosses the axes. Each of these points is called an intercept of the line. The intercepts of a line are the points where the line intercepts, or crosses, the horizontal and vertical axes. To help you remember what “intercept” means, think about the word “intersect.” The two words sound alike and in this case mean the same thing.

Intercepts of a Line

Each of the points at which a line crosses the x-axisx\text{-axis} and the y-axisy\text{-axis} is called an intercept of the line.

Identify the xx- and yy- Intercepts From a Graph

The straight line on the graph below intercepts the two coordinate axes. The point where the line crosses the x-axis is called the xx-intercept. The yy-intercept is the point where the line crosses the y-axis. A line going through two points. One point is on the x-axis and is labeled the x-intercept. The other point is on the y-axis and is labeled y-intercept. In the graph above, the x-intercept occurs when x=2x=-2 and the y-intercept occurs when y=2y=2.  We typically express the intercepts by giving the ordered pair, so we say that the x-intercept above is at the point (2,0)(−2,0) and the y-intercept above is at the point (0,2)(0, 2). Notice that the intercept always occurs where x=0x=0, and the x-intercept always occurs where y=0y=0. Let’s look at the graph of the lines shown below. The graph shows the x y-coordinate plane. The x and y-axis each run from -7 to 7. A line passes through two labeled points, First, notice where each of these lines crosses the x- axis:
Figure: The line crosses the x-axis at: Ordered pair of this point
aa 33 (3,0)(3,0)
bb 44 (4,0)(4,0)
cc 55 (5,0)(5,0)
dd 00 (0,0)(0,0)
Do you see a pattern? For each row, the y- coordinate of the point where the line crosses the x- axis is zero. The point where the line crosses the x- axis has the form (a,0)\left(a,0\right) ; and is called the x-intercept of the line. The x-intercept occurs when y is zero. Now, let's look at the points where these lines cross the y-axis.
Figure: The line crosses the y-axis at: Ordered pair for this point
aa 66 (0,6)(0,6)
bb 3-3 (0,3)(0,-3)
cc 5-5 (0,5)(0,-5)
dd 00 (0,0)(0,0)

xx-intercept and yy-intercept of a line

The x-interceptx\text{-intercept} is the point, (a,0)\left(a,0\right), where the graph crosses the x-axisx\text{-axis}. The x-interceptx\text{-intercept} occurs when y\text{y} is zero. The y-intercepty\text{-intercept} is the point, (0,b)\left(0,b\right), where the graph crosses the y-axisy\text{-axis}. The y-intercepty\text{-intercept} occurs when x\text{x} is zero.
 

example

Find the x- and y-interceptsx\text{- and }y\text{-intercepts} of each line:
1. x+2y=4x+2y=4 The graph shows the x y-coordinate plane. The x and y-axis each run from -7 to 7. A line passes through the points
2. 3xy=63x-y=6 The graph shows the x y-coordinate plane. The x and y-axis each run from -7 to 7. A line passes through the points
3. x+y=5x+y=-5 The graph shows the x y-coordinate plane. The x and y-axis each run from -7 to 7. A line passes through the points
Solution
1.
The graph crosses the x-axis at the point (4,0)(4, 0). The x-intercept is (4,0)(4, 0).
The graph crosses the y-axis at the point (0,2)(0, 2). The y-intercept is (0,2)(0, 2).
2.
The graph crosses the x-axis at the point (2,0)(2, 0). The x-intercept is (2,0)(2, 0)
The graph crosses the y-axis at the point (0,6)(0, −6). The y-intercept is (0,6)(0, −6).
3.
The graph crosses the x-axis at the point (5,0)(−5, 0). The x-intercept is (5,0)(−5, 0).
The graph crosses the y-axis at the point (0,5)(0, −5). The y-intercept is (0,5)(0, −5).
 

try it

[ohm_question]146950[/ohm_question]
In the following video, we provide another example of how to find the intercepts of a line from a graph. https://youtu.be/m5eQ_SjLVuw

Find the Intercepts From an Equation of a Line

Recognizing that the x-interceptx\text{-intercept} occurs when yy is zero and that the y-intercepty\text{-intercept} occurs when xx is zero gives us a method to find the intercepts of a line from its equation.

How to Find the xx-intercept and yy-intercept Given An Equation of a line

To find the x-intercept,x\text{-intercept,} let y=0y=0 and solve for xx. To find the y-intercepty\text{-intercept}, let x=0x=0 and solve for yy.
For example, the linear equation 3y+2x=63y+2x=6 has an x intercept when y=0y=0, so 3(0)+2x=63\left(0\right)+2x=6.

2x=6x=3\begin{array}{r}2x=6\\x=3\end{array}

The x-intercept is (3,0)(3,0). Likewise the y-intercept occurs when x=0x=0.

3y+2(0)=63y=6y=2\begin{array}{r}3y+2\left(0\right)=6\\3y=6\\y=2\end{array}

The y-intercept is (0,2)(0,2).

example

Find the intercepts of 2x+y=62x+y=6 We'll fill in the table below. ... To find the x- intercept, let y=0y=0 :
2x+y=62x+y=6
Substitute 00 for y. 2x+0=62x+\color{red}{0}=6
Add. 2x=62x=6
Divide by 22. x=3x=3
The x-intercept is (3,0)(3, 0).
To find the y- intercept, let x=0x=0 :
2x+y=62x+y=6
Substitute 00 for x. 20+y=62\cdot\color{red}{0}+y=6
Multiply. 0+y=60+y=6
Add. y=6y=6
The y-intercept is (0,6)(0, 6).
... The intercepts are the points (3,0)\left(3,0\right) and (0,6)\left(0,6\right) .
 

try it

[ohm_question]146996[/ohm_question]
 

example

Find the intercepts of 4x3y=124x - 3y=12

Answer: Solution To find the x-intercept,x\text{-intercept,} let y=0y=0.

4x3y=124x - 3y=12
Substitute 00 for yy. 4x30=124x - 3\cdot 0=12
Multiply. 4x0=124x - 0=12
Subtract. 4x=124x=12
Divide by 44. x=3x=3
The x-interceptx\text{-intercept} is (3,0)\left(3,0\right). To find the y-intercepty\text{-intercept}, let x=0x=0.
4x3y=124x - 3y=12
Substitute 00 for xx. 403y=124\cdot 0 - 3y=12
Multiply. 03y=120 - 3y=12
Simplify. 3y=12-3y=12
Divide by 3−3. y=4y=-4
The y-intercepty\text{-intercept} is (0,4)\left(0,-4\right). The intercepts are the points (3,0)\left(-3,0\right) and (0,4)\left(0,-4\right).
4x3y=124x - 3y=12
x y
33 00
00 4-4

 

try it

[ohm_question]146997[/ohm_question]
In the following example we show you how to find the intercepts of a line given in a different form than the examples above. https://youtu.be/vmaMT188ChA

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