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Study Guides > ALGEBRA / TRIG I

Using the Pythagorean Theorem to Solve Problems

Learning Outcomes

  • Use the Pythagorean theorem to find the unknown side length of a right triangle
The Pythagorean theorem is a special property of right triangles that has been used since ancient times. It is named after the Greek philosopher and mathematician Pythagoras who lived around 500500 BCE. Remember that a right triangle has a 90∘90^\circ angle, which we usually mark with a small square in the corner. The side of the triangle opposite the 90∘90^\circ angle is called the hypotenuse, and the other two sides are called the legs. See the triangles below. In a right triangle, the side opposite the 90∘90^\circ angle is called the hypotenuse and each of the other sides is called a leg. Three right triangles are shown. Each has a box representing the right angle. The first one has the right angle in the lower left corner, the next in the upper left corner, and the last one at the top. The two sides touching the right angle are labeled The Pythagorean theorem tells how the lengths of the three sides of a right triangle relate to each other. It states that in any right triangle, the sum of the squares of the two legs equals the square of the hypotenuse.

The Pythagorean Theorem

In any right triangle ΔABC\Delta ABC,

a2+b2=c2{a}^{2}+{b}^{2}={c}^{2}

where cc is the length of the hypotenuse aa and bb are the lengths of the legs. A right triangle is shown. The right angle is marked with a box. Across from the box is side c. The sides touching the right angle are marked a and b.
To solve problems that use the Pythagorean theorem, we will need to find square roots. Previously, we introduced the notation m\sqrt{m} and defined it in this way:

If m=n2, then m=n for n≥0\text{If }m={n}^{2},\text{ then }\sqrt{m}=n\text{ for }n\ge 0

For example, we found that 25\sqrt{25} is 55 because 52=25{5}^{2}=25. We will use this definition of square roots to solve for the length of a side in a right triangle.

example

Use the Pythagorean theorem to find the length of the hypotenuse. Right triangle with legs labeled as 3 and 4. Solution
Step 1. Read the problem.
Step 2. Identify what you are looking for. the length of the hypotenuse of the triangle
Step 3. Name. Choose a variable to represent it. Let c=the length of the hypotenusec=\text{the length of the hypotenuse} .
Step 4. Translate. Write the appropriate formula. Substitute. a2+b2=c2{a}^{2}+{b}^{2}={c}^{2} 32+42=c2{3}^{2}+{4}^{2}={c}^{2}
Step 5. Solve the equation. 9+16=c29+16={c}^{2} 25=c225={c}^{2} 25=c\sqrt{25}={c} 5=c5=c
Step 6. Check:   32+42=52{3}^{2}+{4}^{2}=\color{red}{{5}^{2}} 9+16=?259+16\stackrel{?}{=}25 25+25✓25+25\checkmark
Step 7. Answer the question. The length of the hypotenuse is 55.
 

try it

[ohm_question]146913[/ohm_question]
 

example

Use the Pythagorean theorem to find the length of the longer leg. Right triangle is shown with one leg labeled as 5 and hypotenuse labeled as 13.

Answer: Solution

Step 1. Read the problem.
Step 2. Identify what you are looking for. The length of the leg of the triangle
Step 3. Name. Choose a variable to represent it. Let b=the leg of the triangleb=\text{the leg of the triangle} Label side b .
Step 4. Translate. Write the appropriate formula. Substitute. a2+b2=c2{a}^{2}+{b}^{2}={c}^{2} 52+b2=132{5}^{2}+{b}^{2}={13}^{2}
Step 5. Solve the equation. Isolate the variable term. Use the definition of the square root. Simplify. 25+b2=16925+{b}^{2}=169 b2=144{b}^{2}=144 b=144{b}=\sqrt{144} b=12b=12
Step 6. Check: 52+122=?132{5}^{2}+\color{red}{12}^{2}\stackrel{?}{=}{13}^{2} 25+144=?16925+144\stackrel{?}{=}169 169=169✓169=169\checkmark
Step 7. Answer the question. The length of the leg is 1212.

 

try it

[ohm_question]146914[/ohm_question]
 

example

Kelvin is building a gazebo and wants to brace each corner by placing a 10-inch\text{10-inch} wooden bracket diagonally as shown. How far below the corner should he fasten the bracket if he wants the distances from the corner to each end of the bracket to be equal? Approximate to the nearest tenth of an inch. A picture of a gazebo is shown. Beneath the roof is a rectangular shape. There are two braces from the top to each side. The brace on the left is labeled as 10 inches. From where the brace hits the side to the roof is labeled as x.

Answer: Solution

Step 1. Read the problem.
Step 2. Identify what you are looking for. the distance from the corner that the bracket should be attached
Step 3. Name. Choose a variable to represent it. Let x = the distance from the corner .
Step 4. Translate. Write the appropriate formula. Substitute. a2+b2=c2{a}^{2}+{b}^{2}={c}^{2} x2+x2=102{x}^{2}+{x}^{2}={10}^{2}
Step 5. Solve the equation. Isolate the variable. Use the definition of the square root. Simplify. Approximate to the nearest tenth. 2x2=1002x^2=100 x2=50x^2=50 x=50x=\sqrt{50} b≈7.1b\approx{7.1}  
Step 6. Check: a2+b2=c2{a}^{2}+{b}^{2}={c}^{2} (7.1)2+(7.1)2≈?102(\color{red}{7.1})^2+(\color{red}{7.1})^{2}\stackrel{\text{?}}{\approx}{10}^{2} 50.41+50.41=100.82≈100✓50.41+50.41=100.82\approx{100}\quad\checkmark Yes.
Step 7. Answer the question. Kelvin should fasten each piece of wood approximately 7.1in7.1in from the corner.

 

try it

[ohm_question]146916[/ohm_question] [ohm_question]146918[/ohm_question]
In the following video we show two more examples of how to use the Pythagorean theorem to solve application problems. https://youtu.be/2P0dJxpwFMY

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