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inversa (X^2+8)^{1/5}5-5X 1/5 (X^2+8)^{(-4)/5}(2X)/([(X^2+8)^{1/5)]^2}

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for expand factor rationalize

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focos x=y²

Solution

(14 , 0)

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Foco de uma parábola

Uma parábola é o espaço de pontos tal que a distância a um ponto (o foco) equivale à distância a uma reta (a diretriz)

Equação geral da parábola

4p(x−h)=(y−k)² é a equação geral da parábola de eixo horizontal, com vértice em (h, k),
e distância focal |p|

Reescrever x=y² com a forma da equação geral da parábola: 4· 14 (x−0)=(y−0)²

(h, k)=(0, 0), p=14

A parábola é simétrica ao redor do eixo x (abscissas) e, portanto, o foco estabelece uma distância p do centro (0, 0) ao longo doeixo x (abscissas)

(0+p, 0)

=(0+14 , 0)

Simplificar

(14 , 0)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inversa (X^2+8)^{1/5}5-5X 1/5 (X^2+8)^{(-4)/5}(2X)/([(X^2+8)^{1/5)]^2}

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inversa (X^2+8)^{1/5}5-5X 1/5 (X^2+8)^{(-4)/5}(2X)/([(X^2+8)^{1/5)]^2}

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