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intervalo 14cos(x^2)+19cos(x)+6

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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vértices −2|x|−1

Solution

(0, −1)

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Definição de vértice de função de valor absoluto

Vértices de função de valor absoluto são pontos onde os valores absolutos são zeros

Encontrar os valores absolutos zeros:

Resolver |x|=0: x=0

x=0

Substituir x=0 para encontrar o valor de 'y': (0, −1)

Portanto, o vértice da parábola é

(0, −1)

Solve instead

domínio −2|x|−1

intervalo −2|x|−1

inversa −2|x|−1

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

intervalo 14cos(x^2)+19cos(x)+6

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