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inverse of 3a^2+1-(4+2a^2)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
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range (2x²−1)(−x²−6)

Solution

f(x)≤ 6

Interval Notation

(−∞ , 6]

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Function range definition

The set of values of the dependent variable for which a function is defined

The function range is the combined domain of the inverse functions

Find the inverse function(s) of: (2x²−1)(−x²−6)

Inverse of (2x²−1)(−x²−6): √−11+√−8x+1694 , −√−11+√−8x+1694 , √−11−√−8x+1694 , −√−11−√−8x+1694

√−11+√−8x+1694 , −√−11+√−8x+1694 , √−11−√−8x+1694 , −√−11−√−8x+1694

Find the domain of each inverse function

Domain of √−11+√−8x+1694 : Undefined

Domain of −√−11+√−8x+1694 : Undefined

Domain of √−11−√−8x+1694 : x≤ 6

Domain of −√−11−√−8x+1694 : x≤ 6

Combine the intervals

f(x)≤ 6

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domain (2x²−1)(−x²−6)

inverse (2x²−1)(−x²−6)

intercepts (2x²−1)(−x²−6)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inverse of 3a^2+1-(4+2a^2)

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inverse of 3a^2+1-(4+2a^2)

Solution

Solution steps

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