d/(dn)((n+1)!)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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inversa −3x²−2x+65

Solution

−1+√−15x+193 , −1−√−15x+193

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Definição de função inversa

A função g é o inverso da função f se para y=f(x), x=g(y)

y=−3x²−2x+65

Substitua x por y

x=−3y²−2y+65

Resolver para y, x=−3y²−2y+65

−1+√−15x+193 , −1−√−15x+193

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domínio −3x²−2x+65

intervalo −3x²−2x+65

vértices −3x²−2x+65

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

d/(dn)((n+1)!)

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