inverse of 3a^2+1-(4+2a^2)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for expand factor rationalize

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substituição y^{′ ′}+3y^′=0

Solution

y=−13 e^c₁−3t+c₂

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Definição de imagem de função

O conjunto de valores da variável dependente para a qual uma função é definida

Vértice de 20x²: Mínimo (0, 0)

Para uma parábola ax²+bx+c com vértice (x_v, y_v)
Se a<0 a imagem é f(x)≤ y_v
Se a>0 a imagem é f(x)≥ y_v
a=20, Vértice (x_v, y_v)=(0, 0)

f(x)≥ 0

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Oi, faça uma pergunta sobre intervalo 20x² ou escolha entre as opções abaixo

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inverse of 3a^2+1-(4+2a^2)

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inverse of 3a^2+1-(4+2a^2)

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