inversa (x^4)^5

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

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∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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Steps Examples

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intervalo x²+2x−1−(2x²−3x+6)

Solution

f(x)≤ −34

Interval Notation

(−∞ , −34 ]

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Solution steps

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Focos de uma elipse

Para uma elipse com um eixo maior paralelo ao eixo y (ordenadas), os focos são definidos como (h, k+c), (h, k−c),
onde c=√b²−a² é a distância do centro (h, k) a um foco

(h, k+c), (h, k−c)

Calcular as propriedades da elipse

x²+y²=1: Elipse com centro (h, k)=(0, 0), semieixo maior b=1, semieixo menor a=1

(0, 0+c), (0, 0−c)

Calcular c:

c=√1²−1²: 0

(0, 0+0), (0, 0−0)

Simplificar

(0, 0), (0, 0)

Solve instead

domínio x²+2x−1−(2x²−3x+6)

vértices x²+2x−1−(2x²−3x+6)

inversa x²+2x−1−(2x²−3x+6)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inversa (x^4)^5

Solution

Solution steps

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