eixos (y^2}{25}-\frac{x^2)/9 =1

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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axis y²25 −x²9 =1

Solution

a=5, b=3

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y²25 −x²9 =1

Hyperbola standard equation

(y−k)²a² −(x−h)²b² =1 is the standard equation for an up-down facing hyperbola
with center (h, k), semi-axis a and semi-conjugate-axis b.

Rewrite y²25 −x²9 =1 in the form of a standard hyperbola equation

(y−0)²5² −(x−0)²3² =1

Therefore Hyperbola properties are:

(h, k)=(0, 0), a=5, b=3

And the axes are:

a=5, b=3

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

eixos (y^2}{25}-\frac{x^2)/9 =1

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eixos (y^2}{25}-\frac{x^2)/9 =1

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