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inversa de laplace 5x2−8x−13x2−5
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Solution
5δ(t)−2(2√5+3)√5e−√5t+2(3−2√5)√5e√5t
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Solution steps
Solve by:
One step at a time
L−1{5x2−8x−13x2−5}
Tirar a fração parcial de 5x2−8x−13x2−5:5−2(2√5+3)√5(x+√5)+2(3−2√5)√5(x−√5)
=L−1{5−2(2√5+3)√5(x+√5)+2(3−2√5)√5(x−√5)}
Usar a propriedade de linearidade da transformada inversa de Laplace: Para as funções f(s),g(s) e constantes a,b:L−1{a·f(s)+b·g(s)}=a·L−1{f(s)}+b·L−1{g(s)}