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5x-95/9 = 2/3 x-42/3

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for expand factor rationalize

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regra da cadeia ddx (√2x²+5)

Solution

2x√2x²+5

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ddx (√2x²+5)

Aplicar a regra da cadeia: 12√2x²+5 ddx (2x²+5)

=12√2x²+5 ddx (2x²+5)

ddx (2x²+5)=4x

=12√2x²+5 · 4x

Simplificar 12√2x²+5 · 4x: 2x√2x²+5

=2x√2x²+5

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

5x-95/9 = 2/3 x-42/3

Solution

Solution steps

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5x-9*5/9 = 2/3 x-4*2/3

Solution

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5x-95/9 = 2/3 x-42/3