expandir (2x+3)^3-4x^3

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for expand factor rationalize

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intervalo sin²(x)

Solution

0≤ f(x)≤ 1

Interval Notation

[0, 1]

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Definição de imagem de função

O conjunto de valores da variável dependente para a qual uma função é definida

Encontrar o valor mínimo e máximo em cada intervalo definido e unificar os resultados

Domínio de sin²(x) : −∞ <x<∞

Pontos extremos de sin²(x): Mínimo(πn, 0), Máximo(π2 +πn, 1)

Encontrar a imagem para o intervalo −∞ <x<∞ : 0≤ f(x)≤ 1

Unir as imagens de todos os intervalos de domínio para obter a imagem de função

0≤ f(x)≤ 1

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domínio sin²(x)

periodicidade sin²(x)

inversa sin²(x)

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Oi, faça uma pergunta sobre parity (x⁴)⁵ ou escolha entre as opções abaixo

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

expandir (2x+3)^3-4x^3

Solution

Solution steps

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