intervalo 3a^2+1-(4+2a^2)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for expand factor rationalize

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ddx (e^x²)

Solution

e^x²· 2x

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Definição de função inversa

A função g é o inverso da função f se para y=f(x), x=g(y)

y=64a³+1

Substitua a por y

a=64y³+1

Resolver para y, a=64y³+1

³√a−14

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

intervalo 3a^2+1-(4+2a^2)

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intervalo 3a^2+1-(4+2a^2)

Solution

Solution steps

Number Line

Graph