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focos ((x+3)^2}{25}-\frac{(y-4)^2)/9 =1

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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vértices (x−3)(x+1)

Solution

Mínimo (1, −4)

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Solve by:

Encontre o vértice usando o ponto médio das raízes

Encontrar o vértice usando a forma polinomial

Encontrar o vértice usando a forma da parábola

Encontrar o vértice usando a forma do vértice

One step at a time

y=(x−3)(x+1)

Equação de parábola na forma fatorada

O vértice de uma parábola com concavidade para cima ou para baixo na forma y=a(x−m)(x−n) é a média das raízes x_v=m+n2

y=(x−3)(x+1)

Os parâmetros da parábola são:

a=1, m=3, n=−1

x_v=m+n2

x_v=3+(−1)2

Simplificar

x_v=1

Insira x_v=1 para encontrar o valor y_v

y_v=−4

Portanto, o vértice da parábola é

(1, −4)

Se a<0, então o vértice é um valor máximo
Si a>0, então o vértice é um valor mínimo
a=1

Mínimo (1, −4)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

focos ((x+3)^2}{25}-\frac{(y-4)^2)/9 =1

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focos ((x+3)^2}{25}-\frac{(y-4)^2)/9 =1

Solution

Solution steps

Number Line

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