inversa (z/5)^2

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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fração parcial ∫ 2x²x²−x dx

Solution

2(x+ln|x−1|)+C

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∫ 2x²x²−x dx

Remover a constante: ∫a·f(x)dx=a·∫f(x)dx

=2· ∫ x²x²−x dx

Tirar a fração parcial de x²x²−x : 1+1x−1

=2· ∫ 1+1x−1 dx

Aplicar a regra da soma: ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx

=2(∫ 1dx+∫ 1x−1 dx)

∫ 1dx=x

∫ 1x−1 dx=ln|x−1|

=2(x+ln|x−1|)

Adicionar uma constante à solução

=2(x+ln|x−1|)+C

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inversa (z/5)^2

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inversa (z/5)^2

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Solution steps

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