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intervalo x^2+1

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

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log_□

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∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for expand factor rationalize

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paridade x³−2x²−3xx²−4

Solution

Não é par nem ímpar

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Solution steps

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Definição de imagem de função

O conjunto de valores da variável dependente para a qual uma função é definida

Encontrar o valor mínimo e máximo em cada intervalo definido e unificar os resultados

Domínio de 3√x : x>0

Pontos extremos de 3√x : Nenhum

Encontrar a imagem para o intervalo 0<x<∞ : 0<f(x)<∞

Unir as imagens de todos os intervalos de domínio para obter a imagem de função

f(x)>0

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domínio x³−2x²−3xx²−4

intervalo x³−2x²−3xx²−4

interceptos x³−2x²−3xx²−4

Two-Step Multiply/Divide Equation Examples

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

intervalo x^2+1

Solution

Solution steps

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