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symmetry x2+(y+3)2=16
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Solution
Symmetryaboutthelinex=0
Symmetryabouttheliney=−3
Symmetryaboutthepoint(0,−3)
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x2+(y+3)2=16:Circle with center at (0,−3)and radius r=4
Circle symmetries
Circle in form (x−a)2+(y−b)2=r2exhibits the following symmetries: Symmetry about the line x=a, Symmetry about the line y=b, Symmetry about the center point (a,b)
