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vértices x^2+2x-1-(2x^2-3x+6)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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intervalo x²x²+1

Solution

0≤ f(x)<1

Interval Notation

[0, 1)

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Solution steps

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Definição de imagem de função

O conjunto de valores da variável dependente para a qual uma função é definida

Reescrever como

x²x²+1 =y

Multiplicar ambos os lados por x²+1

x²=y(x²+1)

A imagem é o conjunto de 'y' para os quais o discriminante é maior ou igual a zero

Discriminante x²=y(x²+1): −4y²+4y

−4y²+4y≥ 0 : 0≤ y≤ 1

Verificar se os pontos finais do intervalo da imagem estão inclusos

y=0 : Incluído

y=1 : Excluído

Portanto, a imagem é

0≤ f(x)<1

Solve instead

domínio x²x²+1

inversa x²x²+1

interceptos x²x²+1

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

vértices x^2+2x-1-(2x^2-3x+6)

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vértices x^2+2x-1-(2x^2-3x+6)

Solution

Solution steps

Solve instead

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