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inversa ((x+3)^2}{25}-\frac{(y-4)^2)/9 =1

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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periodicidade sec²(x)

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3.14159…

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12x−9

Reescrever 12 como 3· 4

Reescrever 9 como 3· 3

=3· 4x−3· 3

Fatorar o termo comum 3

=3(4x−3)

Solve instead

domínio sec²(x)

intervalo sec²(x)

inversa sec²(x)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inversa ((x+3)^2}{25}-\frac{(y-4)^2)/9 =1

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