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diameter (x-4)^2+(y+2)^2=25

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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diameter (x−4)²+(y+2)²=25

Solution

d=10

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Circle Diameter

For a circle with radius r the diameter is defined as: d=2r

d=2r

Find the radius

Radius given (x−4)²+(y+2)²=25: r=5

d=2· 5

Refine

d=10

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

diameter (x-4)^2+(y+2)^2=25

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diameter (x-4)^2+(y+2)^2=25

Solution

Solution steps

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