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eixos y=(x+5)^2

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

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^□√☐

□□

log_□

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∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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inverse x³x⁸

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¹¹√x

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Definição de imagem de função

O conjunto de valores da variável dependente para a qual uma função é definida

Encontrar o valor mínimo e máximo em cada intervalo definido e unificar os resultados

Domínio de 1−sec²(x) : πn≤ x<π2 +πn or π2 +πn<x<π+πn

Pontos extremos de 1−sec²(x): Máximo(πn, 0)

Encontrar a imagem para o intervalo 0≤ x<π2 : −∞ <f(x)≤ 0

Encontrar a imagem para o intervalo π2 <x<π: −∞ <f(x)≤ 0

Unir as imagens de todos os intervalos de domínio para obter a imagem de função

f(x)≤ 0 or f(x)≤ 0

f(x)≤ 0

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domain x³x⁸

range x³x⁸

intercepts x³x⁸

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

eixos y=(x+5)^2

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eixos y=(x+5)^2

Solution

Solution steps

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