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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

Solutions > Negative Power Mod Calculator >

inverse of 3^x

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

π

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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Steps Examples

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range 3^x−1

Solution

f(x)>−1

Interval Notation

(−1, ∞ )

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Solution steps

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Ângulo a partir do eixo das abscissas (x)

O ângulo entre um vetor, (

a

b

) e o eixo positivo das abscissas depende do quadrante em que o ponto está situado
Primeiro quadrante: θ=arctan(ba )
Segundo quadrante: θ=π−arctan(|ba |)
Terceiro quadrante: θ=arctan(|ba |)−π
Quarto quadrante: θ=−arctan(|ba |)

O quadrante de (2, −3): 4

O ângulo entre (2, −3) e o eixo das abscissas (x) é

−arctan(|−32 |)

Calcular arctan(θ): −arctan(|−32 |)=−arctan(32 )

=−arctan(32 )

Solve instead

inverse 3^x−1

intercepts 3^x−1

Negative Power Mod Examples

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