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vertices y=2x2
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Solution
Minimum(0,0)
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Solution steps
Solve by:
Find vertex using polynomial form
Find vertex using polynomial form
Find vertex using parabola form
Find vertex using vertex form
Find vertex using averaging the zeros
One step at a time
y=2x2
Parabola equation in polynomial form
The vertex of an up-down facing parabola of the form y=ax2+bx+cis xv=−b2a
The parabola parameters are:
a=2,b=0,c=0
xv=−b2a
xv=−02·2
Simplify
xv=0
Plug in xv=0to find the yvvalue
yv=0
Therefore the parabola vertex is
(0,0)
If a<0,then the vertex is a maximum value If a>0,then the vertex is a minimum value a=2
