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interceptos e^{2ln(x)}

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

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log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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inversa (

1	2	1
6	−1	0
−1	−2	−1

)

Solution

Matriz é singular

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16x²+25y²=100

Ellipse standard equation

(x−h)²a² +(y−k)²b² =1 is the ellipse standard equation
with center (h, k) and a, b are the semi-major and semi-minor axes

Rewrite 16x²+25y²=100 in the form of the standard ellipse equation

(x−0)²(52 )² +(y−0)²2² =1

Therefore ellipse properties are:

(h, k)=(0, 0), a=52 , b=2

a>b therefore a is semi-major axis and b is semi-minor axis

Ellipse with center (h, k)=(0, 0), a=52 , b=2

And the center is:

(0, 0)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

interceptos e^{2ln(x)}

Solution

Solution steps

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