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intervalo ((z-8)^2)/(z^2-64)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

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log_□

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∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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range (z−8)²z²−64

Solution

f(z)<0 or 0<f(z)<1 or f(z)>1

Interval Notation

(−∞ , 0)∪(0, 1)∪(1, ∞ )

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Function range definition

The set of values of the dependent variable for which a function is defined

Find the minimum and maximum value in each defined interval and unite the results

Domain of (z−8)²z²−64 : z<−8 or −8<z<8 or z>8

Simplify (z−8)²z²−64 : z−8z+8

Extreme Points of z−8z+8 : None

Find the range for the interval −∞ <z<−8: 1<f(z)<∞

Find the range for the interval −8<z<8: −∞ <f(z)<0

Find the range for the interval 8<z<∞ : 0<f(z)<1

Combine the ranges of all domain intervals to obtain the function range

f(z)>1 or f(z)<0 or 0<f(z)<1

f(z)<0 or 0<f(z)<1 or f(z)>1

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domain (z−8)²z²−64

inverse (z−8)²z²−64

intercepts (z−8)²z²−64

Order of operations three/four steps with parentheses Examples

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

intervalo ((z-8)^2)/(z^2-64)

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