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substituição y^{\prime \prime}-y=0

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substitution y^{′ ′}−y=0

Solution

y=−√c₁2e^t+c₂ +√c₁e^t+c₂2 , y=−√c₁2e^−t+c₂ +√c₁e^−t+c₂2

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y′ ′ −y=0

Solve using substitution: y=−√c₁2e^t+c₂ +√c₁e^t+c₂2 , y=−√c₁2e^−t+c₂ +√c₁e^−t+c₂2

y=−√c₁2e^t+c₂ +√c₁e^t+c₂2 , y=−√c₁2e^−t+c₂ +√c₁e^−t+c₂2

Order of operations three/four steps with parentheses Examples

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

substituição y^{\prime \prime}-y=0

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