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domain of -4^{x+1}

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

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∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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range √x²+1

Solution

f(x)≥ 1

Interval Notation

[1, ∞ )

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Definição de imagem de função

O conjunto de valores da variável dependente para a qual uma função é definida

Encontrar o valor mínimo e máximo em cada intervalo definido e unificar os resultados

Domínio de (z−8)²z²−64 : z<−8 or −8<z<8 or z>8

Simplificar (z−8)²z²−64 : z−8z+8

Pontos extremos de z−8z+8 : Nenhum

Encontrar a imagem para o intervalo −∞ <z<−8: 1<f(z)<∞

Encontrar a imagem para o intervalo −8<z<8: −∞ <f(z)<0

Encontrar a imagem para o intervalo 8<z<∞ : 0<f(z)<1

Unir as imagens de todos os intervalos de domínio para obter a imagem de função

f(z)>1 or f(z)<0 or 0<f(z)<1

f(z)<0 or 0<f(z)<1 or f(z)>1

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domain √x²+1

inverse √x²+1

intercepts √x²+1

Order of operations two-step without parentheses Examples

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

domain of -4^{x+1}

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domain of -4^{x+1}

Solution

Solution steps

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