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centro 25x2+4y2+100x−40y=400
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Solution
(−2,5)
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25x2+4y2+100x−40y=400
Equação geral de elipse
(x−h)2a2+(y−k)2b2=1é a equação geral da elipse com centro em (h,k)y a,b são os semieixos maior e menor
Reescrever 25x2+4y2+100x−40y=400com a forma da equação geral da elipse
(x−(−2))2(2√6)2+(y−5)2(5√6)2=1
Portanto, as propriedades da elipse são:
(h,k)=(−2,5),a=2√6,b=5√6
b>aportanto bé o semieixo maior e aé o semieixo menor