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intervalo -((x+3)^2)/(20)+1

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transformadora de laplace sin²(θ)

Solution

2s(s²+4)

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L{sin²(θ)}

Usar a seguinte identidade: sin²(x)=12 −cos(2x)12

=L{12 −cos(2θ)12 }

Usar a propriedade de linearidade da transformada de Laplace:
Para as funções f(t), g(t) e constantes a, b: L{a·f(t)+b·g(t)}=a·L{f(t)}+b·L{g(t)}

=L{12 }−12 L{cos(2θ)}

L{12 }: 12s

L{cos(2θ)}: ss²+4

=12s −12 · ss²+4

Simplificar 12s −12 · ss²+4 : 2s(s²+4)

=2s(s²+4)

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inversa de laplace sin²(θ)

Order of operations two-step without parentheses Examples

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

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intervalo -((x+3)^2)/(20)+1

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