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inverse of (2x^2+6)(2x^2-6)

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∫ e^−3xdx

Solution

−13 e^−3x+C

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∫ e^−3xdx

Apply u-substitution: ∫ −13 e^udu

=∫ −13 e^udu

Take the constant out: ∫a·f(x)dx=a·∫f(x)dx

=−13 · ∫ e^udu

Use the common integral: ∫ e^udu=e^u

=−13 e^u

Substitute back u=−3x

=−13 e^−3x

Add a constant to the solution

=−13 e^−3x+C

Verify Result

=−13 e^−3x+C

Order of operations two-step without parentheses Examples

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inverse of (2x^2+6)(2x^2-6)

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inverse of (2x^2+6)(2x^2-6)

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