vertices 6a^2+5a+10-(4a^2+6a+12)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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domain 5x−x²x⁴−25x²

Solution

x<−5 or −5<x<0 or 0<x<5 or x>5

Interval Notation

(−∞ , −5)∪(−5, 0)∪(0, 5)∪(5, ∞ )

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Domain definition

The domain of a function is the set of input or argument values for which the function is real and defined

Find undefined (singularity) points: x=5, x=−5, x=0

The function domain

x<−5 or −5<x<0 or 0<x<5 or x>5

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range 5x−x²x⁴−25x²

inverse 5x−x²x⁴−25x²

intercepts 5x−x²x⁴−25x²

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

vertices 6a^2+5a+10-(4a^2+6a+12)

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vertices 6a^2+5a+10-(4a^2+6a+12)

Solution

Solution steps

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