intervalo 2cos(2x-1)+4

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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range 2cos(2x−1)+4

Solution

2≤ f(x)≤ 6

Interval Notation

[2, 6]

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Function range definition

The set of values of the dependent variable for which a function is defined

The range of the basic cos function is −1≤ cos(2x−1)≤ 1

−1≤ cos(2x−1)≤ 1

Multiply the edges of the range by: 2

−2≤ 2cos(2x−1)≤ 2

Add to the edges of the range: 4

2≤ 2cos(2x−1)+4≤ 6

Therefore the range is

2≤ f(x)≤ 6

Solve instead

domain 2cos(2x−1)+4

periodicity 2cos(2x−1)+4

amplitude 2cos(2x−1)+4

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

intervalo 2cos(2x-1)+4

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