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vertices y=2x^2-1+5x-6

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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intervalo x³−2x²−3xx²−4

Solution

−∞ <f(x)<∞

Interval Notation

(−∞ , ∞ )

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Definição de imagem de função

O conjunto de valores da variável dependente para a qual uma função é definida

Encontrar o valor mínimo e máximo em cada intervalo definido e unificar os resultados

Domínio de x³−2x²−3xx²−4 : x<−2 or −2<x<2 or x>2

Pontos extremos de x³−2x²−3xx²−4 : Máximo(−3.54391…, −6.89260…), Mínimo(−0.57240…, −0.23809…)

Encontrar a imagem para o intervalo −∞ <x<−2: −∞ <f(x)≤ −6.89260…

Encontrar a imagem para o intervalo −2<x<2: −0.23809…≤ f(x)<∞

Encontrar a imagem para o intervalo 2<x<∞ : −∞ <f(x)<∞

Unir as imagens de todos os intervalos de domínio para obter a imagem de função

f(x)≤ −6.89260… or f(x)≥ −0.23809… or −∞ <f(x)<∞

−∞ <f(x)<∞

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domínio x³−2x²−3xx²−4

inversa x³−2x²−3xx²−4

interceptos x³−2x²−3xx²−4

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

vertices y=2x^2-1+5x-6

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vertices y=2x^2-1+5x-6

Solution

Solution steps

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