Solutions > Logarithm Properties Calculator >

limit as x approaches infinity of e^xcos(x)

Topic

Full pad

`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for expand factor rationalize

See All

area

asymptotes

critical points

derivative

domain

eigenvalues

eigenvectors

expand

extreme points

factor

implicit derivative

inflection points

intercepts

inverse

laplace

inverse laplace

partial fractions

range

slope

simplify

solve for

tangent

taylor

vertex

geometric test

alternating test

telescoping test

pseries test

root test

Steps Examples

Generated by AI

ângulo (2, −3)

Solution

−arctan(32 )

Degrees

−56.30993…^◦

Decimal

−0.98279…

Show Steps

Hide Steps

Solution steps

One step at a time

Ângulo a partir do eixo das abscissas (x)

O ângulo entre um vetor, (

a

b

) e o eixo positivo das abscissas depende do quadrante em que o ponto está situado
Primeiro quadrante: θ=arctan(ba )
Segundo quadrante: θ=π−arctan(|ba |)
Terceiro quadrante: θ=arctan(|ba |)−π
Quarto quadrante: θ=−arctan(|ba |)

O quadrante de (2, −3): 4

O ângulo entre (2, −3) e o eixo das abscissas (x) é

−arctan(|−32 |)