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sequence type a_{1}=-2,d=3

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

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∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for expand factor rationalize

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focos y=−3x²−2x+65

Solution

(−13 , 1720 )

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Foco de uma parábola

Uma parábola é o espaço de pontos tal que a distância a um ponto (o foco) equivale à distância a uma reta (a diretriz)

Equação geral da parábola

4p(y−k)=(x−h)² é a equação geral da parábola de eixo vertical, com vértice em (h, k),
e distância focal |p|

Reescrever y=−3x²−2x+65 com a forma da equação geral da parábola

4(−512 )(y−1915 )=(x−(−13 ))²

(h, k)=(−13 , 1915 ), p=−512

A parábola é simétrica ao redor do eixo y (ordenadas) e, portanto, o foco estabelece uma distância p do centro (−13 , 1915 ) ao longo do eixo y (ordenadas)

(−13 , 1915 +p)

=(−13 , 1915 +(−512 ))

Simplificar

(−13 , 1720 )

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

sequence type a_{1}=-2,d=3

Solution

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