convergence a_{n}=(3^{n+2})/(5^n)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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convergence a_n=3ⁿ⁺²5ⁿ

Solution

converges

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a_n=3ⁿ⁺²5ⁿ

Convergence of a sequence

The sequence a_n is convergent if lim_{n→ ∞}(a_n) exists and is finite

lim_{n→ ∞}(3ⁿ⁺²5ⁿ )=0

Hence the sequence converges

converges

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sequence type a_n=3ⁿ⁺²5ⁿ

first term a_n=3ⁿ⁺²5ⁿ

nth term a_n=3ⁿ⁺²5ⁿ

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

convergence a_{n}=(3^{n+2})/(5^n)

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