convergence a_{1}=-2, d=3

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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√☐

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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convergence a₁=−2, d=3

Solution

diverges

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a₁=−2, d=3

Find the sequence type for a₁=−2, d=3: arithmetic sequence: d=3, a_n=3n−5

Convergence of a sequence

The sequence a_n is convergent if lim_{n→ ∞}(a_n) exists and is finite

lim_{n→ ∞}(3n−5)=∞

Hence the sequence diverges

diverges

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sequence type a₁=−2, d=3

first term a₁=−2, d=3

nth term a₁=−2, d=3

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

convergence a_{1}=-2, d=3

Solution

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