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inverse of (x(x-1)^2)/(x^2-1)

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∫ x²−25x²+4x−5 dx

Solution

x−4ln|x−1|+C

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∫ x²−25x²+4x−5 dx

Tirar a fração parcial de x²−25x²+4x−5 : 1−4x−1

=∫ 1−4x−1 dx

Aplicar a regra da soma: ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx

=∫ 1dx−∫ 4x−1 dx

∫ 1dx=x

∫ 4x−1 dx=4ln|x−1|

=x−4ln|x−1|

Adicionar uma constante à solução

=x−4ln|x−1|+C

Verify Result

=x−4ln|x−1|+C

Order of operations two-step without parentheses Examples

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

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inverse of (x(x-1)^2)/(x^2-1)

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inverse of (x(x-1)^2)/(x^2-1)

Solution

Solution steps

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