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amplitude of cos(2x+5)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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simplificar 2a³· 4a³

Solution

8a⁶

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2a³· 4a³

Multiplicar os números: 2· 4=8

=8a³a³

Aplicar as propriedades dos expoentes: a^b· a^c=a^b+c

a³a³=a³⁺³

=8a³⁺³

Somar: 3+3=6

=8a⁶

Solve instead

f(a)=2a³· 4a³

dda (2a³· 4a³)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

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amplitude of cos(2x+5)

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