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intervalo 4x(4x-2)(x^2-3)

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eixos y=x²+x+1

Solution

x=−12

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y=x²+x+1

Equação geral da parábola

4p(y−k)=(x−h)² é a equação geral da parábola de eixo vertical, com vértice em (h, k),
e distância focal |p|

Reescrever y=x²+x+1 com a forma da equação geral da parábola

4· 14 (y−34 )=(x−(−12 ))²

Portanto, as propriedades da parábola são:

(h, k)=(−12 , 34 ), p=14

A parábola possui a forma 4p(y−k)=(x−h)² e é simétrica ao redor do eixo y.
O eixo de simetria é uma reta paralela ao eixoyque intercepta o vértice.

x=−12

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

intervalo 4x(4x-2)(x^2-3)

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