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inversa de laplace ((2x^3+11x^2+5x))/((2x^2+x))

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focos 25x²+4y²+100x−40y=400

Solution

(−2, 5+3√14), (−2, 5−3√14)

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Focos de uma elipse

Para uma elipse com um eixo maior paralelo ao eixo y (ordenadas), os focos são definidos como (h, k+c), (h, k−c),
onde c=√b²−a² é a distância do centro (h, k) a um foco

(h, k+c), (h, k−c)

Calcular as propriedades da elipse

25x²+4y²+100x−40y=400: Elipse com centro (h, k)=(−2, 5), semieixo maior b=5√6, semieixo menor a=2√6

(−2, 5+c), (−2, 5−c)

Calcular c:

c=√(5√6)²−(2√6)²: 3√14

(−2, 5+3√14), (−2, 5−3√14)

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inversa de laplace ((2x^3+11x^2+5x))/((2x^2+x))

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inversa de laplace ((2x^3+11x^2+5x))/((2x^2+x))

Solution

Solution steps

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