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inverse of ((z-8)^2)/(z^2-64)

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eixos 16x²+25y²=100

Solution

semieixo maior a=52 , semieixo menor b=2

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16x²+25y²=100

Equação geral de elipse

(x−h)²a² +(y−k)²b² =1 é a equação geral da elipse
com centro em (h, k) y a, b são os semieixos maior e menor

Reescrever 16x²+25y²=100 com a forma da equação geral da elipse

(x−0)²(52 )² +(y−0)²2² =1

Portanto, as propriedades da elipse são:

(h, k)=(0, 0), a=52 , b=2

a>b portanto a é o semieixo maior e b é o semieixo menor

Elipse com centro (h, k)=(0, 0), semieixo maior a=52 , semieixo menor b=2

Solve instead

simetria 16x²+25y²=100

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inverse of ((z-8)^2)/(z^2-64)

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inverse of ((z-8)^2)/(z^2-64)

Solution

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