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substituição y^{\prime \prime}+y=0

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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log_□

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ddx

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paridade 4x³−x²+x−2−(x²−3)

Solution

Não é par nem ímpar

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Definição de paridade

Função par: Uma função é par se f(−x)=f(x) para todos x∈ℝ
Função ímpar: Uma função é ímpar se f(−x)=−f(x) para todos x∈ℝ

f(x): 4x³−2x²+x+1

f(−x): −4x³−2x²−x+1

−f(x): −4x³+2x²−x−1

Verificar paridade de 4x³−2x²+x+1

Verificar se é par: Falso

Verificar se é ímpar: Falso

Não é par nem ímpar

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domínio 4x³−x²+x−2−(x²−3)

intervalo 4x³−x²+x−2−(x²−3)

interceptos 4x³−x²+x−2−(x²−3)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

substituição y^{\prime \prime}+y=0

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