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intervalo (X^2+8)^{1/5}5-5X 1/5 (X^2+8)^{(-4)/5}(2X)/([(X^2+8)^{1/5)]^2}

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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symmetry x²+(y+3)²=16

Solution

Symmetry about the line x=0

Symmetry about the line y=−3

Symmetry about the point (0, −3)

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x²+(y+3)²=16: Circle with center at (0, −3) and radius r=4

Circle symmetries

Circle in form (x−a)²+(y−b)²=r² exhibits the following symmetries:
Symmetry about the line x=a,
Symmetry about the line y=b,
Symmetry about the center point (a, b)

Therefore the symmetries are:

Symmetry about the line x=0

Symmetry about the line y=−3

Symmetry about the point (0, −3)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

intervalo (X^2+8)^{1/5}5-5X 1/5 (X^2+8)^{(-4)/5}(2X)/([(X^2+8)^{1/5)]^2}

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intervalo (X^2+8)^{1/5}5-5X 1/5 (X^2+8)^{(-4)/5}(2X)/([(X^2+8)^{1/5)]^2}

Solution

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