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vertices (x+5)^2

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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intervalo (2x²+6)(2x²−6)

Solution

f(x)≥ −36

Interval Notation

[−36, ∞ )

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Solution steps

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Definição de imagem de função

O conjunto de valores da variável dependente para a qual uma função é definida

A imagem da função é o domínio combinado das funções inversas

Encontrar a(s) função(ões) inversa(s) de: (2x²+6)(2x²−6)

Inversa de (2x²+6)(2x²−6): √√x+362 , −√√x+362 , √−√x+362 , −√−√x+362

√√x+362 , −√√x+362 , √−√x+362 , −√−√x+362

Encontrar o domínio de cada função inversa

Domínio de √√x+362 : x≥ −36

Domínio de −√√x+362 : x≥ −36

Domínio de √−√x+362 : x=−36

Domínio de −√−√x+362 : x=−36

Combinar os intervalos

f(x)≥ −36

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domínio (2x²+6)(2x²−6)

inversa (2x²+6)(2x²−6)

interceptos (2x²+6)(2x²−6)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

vertices (x+5)^2

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vertices (x+5)^2

Solution

Solution steps

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